09 Oct Does each of these graphs have an Euler circuit? If so, find it Does
11. Does each of these graphs have an Euler circuit? If so, find it.
12. Does each of these graphs have an Euler circuit? If so, find it.
13. Eulerize this graph using as few edge duplications as possible. Then, find an Euler circuit.
17. Does each of these graphs have at least one Hamiltonian circuit? If so, find one.
19. A company needs to deliver product to each of their 5 stores around the Dallas, TX area. Driving distances between the stores are shown below. Find a route for the driver to follow, returning to the distribution center in Fort Worth:
a. Using Nearest Neighbor starting in Fort Worth
b. Using Repeated Nearest Neighbor
c. Using Sorted Edges
21. When installing fiber optics, some companies will install a sonet ring; a full loop of cable connecting multiple locations. This is used so that if any part of the cable is damaged it does not interrupt service, since there is a second connection to the hub. A company has 5 buildings. Costs (in thousands of dollars) to lay cables between pairs of buildings are shown below. Find the circuit that will minimize cost:
a. Using Nearest Neighbor starting at building A
b. Using Repeated Nearest Neighbor
c. Using Sorted Edges
23. Find a minimum cost spanning tree for the graph you created in problem #3
Graph Theory 117
© David Lippman Creative Commons BY-SA
Graph Theory and Network Flows In the modern world, planning efficient routes is essential for business and industry, with
applications as varied as product distribution, laying new fiber optic lines for broadband
internet, and suggesting new friends within social network websites like Facebook.
This field of mathematics started nearly 300 years ago as a look into a mathematical puzzle
(we’ll look at it in a bit). The field has exploded in importance in the last century, both
because of the growing complexity of business in a global economy and because of the
computational power that computers have provided us.
Graphs
Drawing Graphs
Example 1
Here is a portion of a housing development from Missoula, Montana1. As part of her job, the
development’s lawn inspector has to walk down every street in the development making sure
homeowners’ landscaping conforms to the community requirements.
1 Sam Beebe. http://www.flickr.com/photos/sbeebe/2850476641/, CC-BY
118
Naturally, she wants to minimize the amount of walking she has to do. Is it possible for her
to walk down every street in this development without having to do any backtracking?
While you might be able to answer that question just by looking at the picture for a while, it
would be ideal to be able to answer the question for any picture regardless of its complexity.
To do that, we first need to simplify the picture into a form that is easier to work with. We
can do that by drawing a simple line for each street. Where streets intersect, we will place a
dot.
This type of simplified picture is called a graph.
Graphs, Vertices, and Edges
A graph consists of a set of dots, called vertices, and a set of edges connecting pairs of
vertices.
While we drew our original graph to correspond with the picture we had, there is nothing
particularly important about the layout when we analyze a graph. Both of the graphs below
are equivalent to the one drawn above since they show the same edge connections between
the same vertices as the original graph.
You probably already noticed that we are using the term graph differently than you may have
used the term in the past to describe the graph of a mathematical function.
A
B
C
D
E
F
G
H
I
J
K L
M
N
O P Q
R
A
B
C
D
E F
G
H
I
J
K
L
M
N O
P Q
R
A B C
D E F
G
H
I J
K
L
M
N
O
P
Q
R
Graph Theory 119
Example 2
Back in the 18th century in the Prussian city of
Königsberg, a river ran through the city and seven
bridges crossed the forks of the river. The river
and the bridges are highlighted in the picture to
the right2.
As a weekend amusement, townsfolk would see if
they could find a route that would take them
across every bridge once and return them to
where they started.
Leonard Euler (pronounced OY-lur), one of the
most prolific mathematicians ever, looked at this problem in 1735, laying the foundation for
graph theory as a field in mathematics. To analyze this problem, Euler introduced edges
representing the bridges:
Since the size of each land mass it is not relevant to the question of bridge crossings, each
can be shrunk down to a vertex representing the location:
Notice that in this graph there are two edges connecting the north bank and island,
corresponding to the two bridges in the original drawing. Depending upon the interpretation
of edges and vertices appropriate to a scenario, it is entirely possible and reasonable to have
more than one edge connecting two vertices.
While we haven’t answered the actual question yet of whether or not there is a route which
crosses every bridge once and returns to the starting location, the graph provides the
foundation for exploring this question.
2 Bogdan Giuşcă. http://en.wikipedia.org/wiki/File:Konigsberg_bridges.png
North Bank
Island
South Bank
East Bank
EB
NB
SB
I
120
Definitions
While we loosely defined some terminology earlier, we now will try to be more specific.
Vertex
A vertex is a dot in the graph that could represent an intersection of streets, a land
mass, or a general location, like “work” or “school”. Vertices are often connected by
edges. Note that vertices only occur when a dot is explicitly placed, not whenever two
edges cross. Imagine a freeway overpass – the freeway and side street cross, but it is
not possible to change from the side street to the freeway at that point, so there is no
intersection and no vertex would be placed.
Edges
Edges connect pairs of vertices. An edge can represent a physical connection between
locations, like a street, or simply that a route connecting the two locations exists, like
an airline flight.
Loop
A loop is a special type of edge that connects a vertex to itself. Loops are not used
much in street network graphs.
Degree of a vertex
The degree of a vertex is the number of edges meeting at that vertex. It is possible for
a vertex to have a degree of zero or larger.
Path
A path is a sequence of vertices using the edges. Usually we are interested in a path
between two vertices. For example, a path from vertex A to vertex M is shown below.
It is one of many possible paths in this graph.
Degree 0 Degree 1 Degree2 Degree 3 Degree 4
A B C D
E F G H
J K L M
Graph Theory 121
Circuit
A circuit is a path that begins and ends at the same vertex. A circuit starting and
ending at vertex A is shown below.
Connected
A graph is connected if there is a path from any vertex to any other vertex. Every
graph drawn so far has been connected. The graph below is disconnected; there is no
way to get from the vertices on the left to the vertices on the right.
Weights
Depending upon the problem being solved, sometimes weights are assigned to the
edges. The weights could represent the distance between two locations, the travel time,
or the travel cost. It is important to note that the distance between vertices in a graph
does not necessarily correspond to the weight of an edge.
Try it Now 1
1. The graph below shows 5 cities. The weights on the edges represent the airfare for a
one-way flight between the cities.
a. How many vertices and edges does the graph have?
b. Is the graph connected?
c. What is the degree of the vertex representing LA?
d. If you fly from Seattle to Dallas to Atlanta, is that a path or a circuit?
e. If you fly from LA to Chicago to Dallas to LA, is that a path or a circuit?
Seattle
LA
Chicago
Dallas
Atlanta
$165
$150
$120
$85
$75
$100
$70
$145
$140 $170
A B C D
E F G H
J K L M
122
Shortest Path When you visit a website like Google Maps or use your Smartphone to ask for directions
from home to your Aunt’s house in Pasadena, you are usually looking for a shortest path
between the two locations. These computer applications use representations of the street
maps as graphs, with estimated driving times as edge weights.
While often it is possible to find a shortest path on a small graph by guess-and-check, our
goal in this chapter is to develop methods to solve complex problems in a systematic way by
following algorithms. An algorithm is a step-by-step procedure for solving a problem.
Dijkstra’s (pronounced dike-stra) algorithm will find the shortest path between two vertices.
Dijkstra’s Algorithm
1. Mark the ending vertex with a distance of zero. Designate this vertex as current.
2. Find all vertices leading to the current vertex. Calculate their distances to the end.
Since we already know the distance the current vertex is from the end, this will just
require adding the most recent edge. Don’t record this distance if it is longer than a
previously recorded distance.
3. Mark the current vertex as visited. We will never look at this vertex again.
4. Mark the vertex with the smallest distance as current, and repeat from step 2.
Example 3
Suppose you need to travel from Tacoma, WA (vertex T) to Yakima, WA (vertex Y).
Looking at a map, it looks like driving through Auburn (A) then Mount Rainier (MR) might
be shortest, but it’s not totally clear since that road is probably slower than taking the major
highway through North Bend (NB). A graph with travel times in minutes is shown below.
An alternate route through Eatonville (E) and Packwood (P) is also shown.
Step 1: Mark the ending vertex
with a distance of zero. The
distances will be recorded in
[brackets] after the vertex name.
96 79
27
76 96
57
20
36 104
T
A
NB
MR
E P
Y
96 79
27
76 96
57
20
36 104
T
A
NB
MR
E P
Y [0]
Graph Theory 123
Step 2: For each vertex leading to
Y, we calculate the distance to the
end. For example, NB is a
distance of 104 from the end, and
MR is 96 from the end.
Remember that distances in this
case refer to the travel time in
minutes.
Step 3 & 4: We mark Y as visited, and mark the vertex with the smallest recorded distance
as current. At this point, P will be designated current. Back to step 2.
Step 2 (#2): For each vertex leading to P (and not leading to a visited vertex) we find the
distance from the end. Since E is 96 minutes from P, and we’ve already calculated P is 76
minutes from Y, we can compute
that E is 96+76 = 172 minutes
from Y.
If we make the same computation
for MR, we’d calculate 76+27 =
103. Since this is larger than the
previously recorded distance from
Y to MR, we will not replace it.
Step 3 & 4 (#2): We mark P as visited, and designate the vertex with the smallest recorded
distance as current: MR. Back to step 2.
Step 2 (#3): For each vertex
leading to MR (and not leading to
a visited vertex) we find the
distance to the end. The only
vertex to be considered is A, since
we’ve already visited Y and P.
Adding MR’s distance 96 to the
length from A to MR gives the
distance 96+79 = 175 minutes
from A to Y.
Step 3 & 4 (#3): We mark MR as visited, and designate the vertex with smallest recorded
distance as current: NB. Back to step 2.
96
79
27
76 96
57
20
36 104
T
A
NB [104]
MR [96]
E P [76]
Y [0]
96
79
27
76 96
57
20
36 104
T
A
NB [104]
MR [96]
E [172] P [76]
Y [0]
96
79
27
76 96
57
20
36 104
T
A [175]
NB [104]
MR [96]
E [172] P [76]
Y [0]
124
Step 2 (#4): For each vertex
leading to NB, we find the
distance to the end. We know the
shortest distance from NB to Y is
104 and the distance from A to
NB is 36, so the distance from A
to Y through NB is 104+36 = 140.
Since this distance is shorter than
the previously calculated distance
from Y to A through MR, we
replace it.
Step 3 & 4 (#4): We mark NB as visited, and designate A as current, since it now has the
shortest distance.
Step 2 (#5): T is the only
non-visited vertex leading to
A, so we calculate the
distance from T to Y through
A: 20+140 = 160 minutes.
Step 3 & 4 (#5): We mark A as visited, and designate E as current.
Step 2 (#6): The only non-visited vertex leading to E is T. Calculating the distance from T
to Y through E, we compute 172+57 = 229 minutes. Since this is longer than the existing
marked time, we do not replace it.
Step 3 (#6): We mark E as visited. Since all vertices have been visited, we are done.
From this, we know that the shortest path from Tacoma to Yakima will take 160 minutes.
Tracking which sequence of edges yielded 160 minutes, we see the shortest path is T-A-NB-
Y.
Dijkstra’s algorithm is an optimal algorithm, meaning that it always produces the actual
shortest path, not just a path that is pretty short, provided one exists. This algorithm is also
efficient, meaning that it can be implemented in a reasonable amount of time. Dijkstra’s
algorithm takes around V2 calculations, where V is the number of vertices in a graph3. A
graph with 100 vertices would take around 10,000 calculations. While that would be a lot to
do by hand, it is not a lot for computer to handle. It is because of this efficiency that your
car’s GPS unit can compute driving directions in only a few seconds.
3 It can be made to run faster through various optimizations to the implementation.
96
79
27
76 96
57
20
36 104
T
A [140]
NB [104]
MR [96]
E [172] P [76]
Y [0]
96
79
27
76 96
57
20
36 104
T [160]
A [140]
NB [104]
MR [96]
E [172] P [76]
Y [0]
Graph Theory 125
In contrast, an inefficient algorithm might try to list all possible paths then compute the
length of each path. Trying to list all possible paths could easily take 1025 calculations to
compute the shortest path with only 25 vertices; that’s a 1 with 25 zeros after it! To put that
in perspective, the fastest computer in the world would still spend over 1000 years analyzing
all those paths.
Example 4
A shipping company needs to route a package from Washington, D.C. to San Diego, CA. To
minimize costs, the package will first be sent to their processing center in Baltimore, MD
then sent as part of mass shipments between their various processing centers, ending up in
their processing center in Bakersfield, CA. From there it will be delivered in a small truck to
San Diego.
The travel times, in hours, between their processing centers are shown in the table below.
Three hours has been added to each travel time for processing. Find the shortest path from
Baltimore to Bakersfield.
While we could draw a graph, we can also work directly from the table.
Step 1: The ending vertex, Bakersfield, is marked as current.
Step 2: All cities connected to Bakersfield, in this case Denver and Dallas, have their
distances calculated; we’ll mark those distances in the column headers.
Step 3 & 4: Mark Bakersfield as visited. Here, we are doing it by shading the corresponding
row and column of the table. We mark Denver as current, shown in bold, since it is the
vertex with the shortest distance.
Baltimore Denver Dallas Chicago Atlanta Bakersfield
Baltimore * 15 14
Denver * 18 24 19
Dallas * 18 15 25
Chicago 15 18 18 * 14
Atlanta 14 24 15 14 *
Bakersfield 19 25 *
Baltimore
Denver
[19]
Dallas
[25]
Chicago Atlanta Bakersfield
[0]
Baltimore * 15 14
Denver * 18 24 19
Dallas * 18 15 25
Chicago 15 18 18 * 14
Atlanta 14 24 15 14 *
Bakersfield 19 25 *
126
Step 2 (#2): For cities connected to Denver, calculate distance to the end. For example,
Chicago is 18 hours from Denver, and Denver is 19 hours from the end, the distance for
Chicago to the end is 18+19 = 37 (Chicago to Denver to Bakersfield). Atlanta is 24 hours
from Denver, so the distance to the end is 24+19 = 43 (Atlanta to Denver to Bakersfield).
Step 3 & 4 (#2): We mark Denver as visited and mark Dallas as current.
Step 2 (#3): For cities connected to Dallas, calculate the distance to the end. For Chicago,
the distance from Chicago to Dallas is 18 and from Dallas to the end is 25, so the distance
from Chicago to the end through Dallas would be 18+25 = 43. Since this is longer than the
currently marked distance for Chicago, we do not replace it. For Atlanta, we calculate 15+25
= 40. Since this is shorter than the currently marked distance for Atlanta, we replace the
existing distance.
Step 3 & 4 (#3): We mark Dallas as visited, and mark Chicago as current.
Step 2 (#4): Baltimore and Atlanta are the only non-visited cities connected to Chicago. For
Baltimore, we calculate 15+37 = 52 and mark that distance. For Atlanta, we calculate 14+37
= 51. Since this is longer than the existing distance of 40 for Atlanta, we do not replace that
distance.
Baltimore
Denver
[19]
Dallas
[25]
Chicago
[37]
Atlanta
[43]
Bakersfield
[0]
Baltimore * 15 14
Denver * 18 24 19
Dallas * 18 15 25
Chicago 15 18 18 * 14
Atlanta 14 24 15 14 *
Bakersfield 19 25 *
Baltimore
Denver
[19]
Dallas
[25]
Chicago
[37]
Atlanta
[40]
Bakersfield
[0]
Baltimore * 15 14
Denver * 18 24 19
Dallas * 18 15 25
Chicago 15 18 18 * 14
Atlanta 14 24 15 14 *
Bakersfield 19 25 *
Graph Theory 127
Step 3 & 4 (#4): Mark Chicago as visited and Atlanta as current.
Step 2 (#5): The distance from Atlanta to Baltimore is 14. Adding that to the distance
already calculated for Atlanta gives a total distance of 14+40 = 54 hours from Baltimore to
Bakersfield through Atlanta. Since this is larger than the currently calculated distance, we do
not replace the distance for Baltimore.
Step 3 & 4 (#5): We mark Atlanta as visited. All cities have been visited and we are done.
The shortest route from Baltimore to Bakersfield will take 52 hours, and will route through
Chicago and Denver.
Try it Now 2
Find the shortest path between vertices A and G in the graph below.
Euler Circuits and the Chinese Postman Problem In the first section, we created a graph of the Königsberg bridges and asked whether it was
possible to walk across every bridge once. Because Euler first studied this question, these
types of paths are named after him.
Euler Path
An Euler path is a path that uses every edge in a graph with no repeats. Being a path,
it does not have to return to the starting vertex.
Baltimore
[52]
Denver
[19]
Dallas
[25]
Chicago
[37]
Atlanta
[40]
Bakersfield
[0]
Baltimore * 15 14
Denver * 18 24 19
Dallas * 18 15 25
Chicago 15 18 18 * 14
Atlanta 14 24 15 14 *
Bakersfield 19 25 *
7
4 4
5
2
1 2
6
6
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